A Spring is pulled to 10cm and held in place with a force of 500N .what is the spring constant

We are given:

extension of the spring (x) = 10 cm OR 0.1 m

Force applied to keep it in position (F) = 500 N

Solving for the spring constant:

We know that F = kx (when the spring is extended)

replacing the variables with the given values

500 = k * 0.1

k = 5000 N/m

This means that to extend the spring by 1 m, we have to apply a force of 5000 N

be subject to a force andchange its motion