What is the frictional force between a box and the floor it is being pulled across if, the kinetic coefficient of friction is 0.27 and the box weighs 38 N?
A 140.7 N
B 100.6 N
C. 37.7 N
D. 10.3 N

If the pulling is done parallel to the floor with constant velocity, then the box is in equilibrium. In particular, the weight and normal force cancel, so that

n = 38 N

The friction force is proportional to the normal force by a factor of 0.27, so that

f = 0.27 (38 N) ≈ 10.3 N

and so the answer is D.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr