A simple pendulum consisting of a bob of mass mmm attached to a string of length LLL swings with a period TTT. Part A If the bob's mass is doubled, approximately what will the pendulum's new period be? View Available Hint(s) If the bob's mass is doubled, approximately what will the pendulum's new period be? T/2T/2 TTT 2–√T2T 2T2T Submit

come closer and become far apart and become steam/gas

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft