A point charge Q is placed at the center of a cube of side l. what is the flux through one face of the cube?

Explanation:

A point charge Q is placed at the center of a cube of side l.

We need to find the flux through one face of the cube. Let the flux is .

There are 6 faces in a cube.

According to Gauss's law, net flux is given by :

As there are 6 faces of a cube, flux through one surface is :

So, the flux through one face of the cube is .

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft