A stone is thrown downwards from the edge of a cliff with a speed of 5.0 ms. It hits the ground 2.0 s later. What is the height of the cliff?

20 m

Explanation:

Step-by-step explanation:

We are given that

Initial horizontal speed ,u_x=15 m/su

x

=15m/s

Time, t=2 s

Initial vertical velocity, u_y=0u

y

=0

We know that

h=u_yt+\frac{1}{2}gt^2h=u

y

t+

2

1

gt

2

Where g=-9.8m/s^2g=−9.8m/s

2

Using the formula

h=0(2)+\frac{1}{2}(-9.8)(2)^2h=0(2)+

2

1

(−9.8)(2)

2

h=-19.6 m\approx -20 mh=−19.6m≈−20m

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!