A number minus four times a second number is at least –4. Three times the first number, then added to the second number, is more than –3. If x represents the first number and y represents the second number, which system of inequalities best represents the problem situation? 2x−4y≥−4 3x+2y>−3 2 x minus 4 y is greater than or equal to negative 4, , 3 x plus 2 y is greater than negative 3, , , x−4y≥−4 3x+y>−3 x minus 4 y is greater than or equal to negative 4, , 3 x plus y is greater than negative 3, , , 2x−4y<−4 3x+y>−3 2x−4y<−4, , 3 x plus y is greater than negative 3, , , x−4y≤−4 3x+y>−3

x - 4y ≥ -4

3x + y ≥ - 3

Explanation:

The first condition says that A number minus four times a second number is at least –4. So, taking x as first number and y as second number, we get:

x - 4y ≥ -4

Similarly, the other condition says that Three times the first number, then added to the second number, is more than –3. This will be represented as:

3x + y ≥ - 3

So, the system of inequalities that best represents the problem situation is:

x - 4y ≥ -4

3x + y ≥ - 3

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explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards