Physics, 04.11.2020 21:40, surfergirlmymy

Mastering Problems 57. Ranking Task Rank the following objects according
to the magnitude of the acceleration, from least to
greatest. Specifically indicate any ties,
A. A falling acorn accelerates from 0.50 m/s to
10.3 m/s in 1.0 s.
B. A car accelerates from 20 m/s to rest in 1.0 s.
C. A centipede accelerates from 0.40 cm/s to 2.0 cm/s
in 0.50 s.
D. While
being hit, a golf ball accelerates from rest to
4.3 m/s in 0.40 s.
E. A jogger accelerates from 2.0 m/s to 1.0 m/s in 8.3 s.

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Answers

answered: darlenepitre

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

In physics, acceleration (a) is the rate at which velocity changes (Δv) with time (t).

We will calculate the acceleration for each scenario using the following expression.

$a = \frac{v-u}{t}$

where,

u: initial velocityv: final velocityA. A falling acorn accelerates from 0.50 m/s to 10.3 m/s in 1.0 s.

Data

u: 0.50 m/sv: 10.3 m/st: 1.0 s

$a = \frac{10.3m/s-0.50m/s}{1.0s} = 9.8 m/s^{2}$

B. A car accelerates from 20 m/s to rest in 1.0 s.

Data

u: 20 m/sv: 0 m/s (rest)t: 1.0 s

$a = \frac{0m/s-20m/s}{1.0s} = -20 m/s^{2}\\\\|a| = 20 m/s^{2}$

C. A centipede accelerates from 0.40 cm/s to 2.0 cm/s in 0.50 s.

Data

u: 0.40 cm/sv: 2.0 cm/st: 0.50 s

$a = \frac{2.0cm/s-0.40cm/s}{0.50s} = 3.2cm/s^{2} \times \frac{1m}{100cm} = 0.032 m/s^{2}$

D. While being hit, a golf ball accelerates from rest to 4.3 m/s in 0.40 s.

Data

u: 0 m/s (rest)v: 4.3 m/st: 0.40 s

$a = \frac{4.3m/s-0m/s}{0.40s} = 11 m/s^{2}$

E. A jogger accelerates from 2.0 m/s to 1.0 m/s in 8.3 s.

Data

u: 2.0 m/sv: 1.0 m/st: 8.3 s

$a = \frac{1.0m/s-2.0m/s}{8.3s} = -0.12 m/s^{2}\\\\|a| = 0.12 m/s^{2}$

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

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answered: nawafcanada

C , E , A , D , B

Explanation:

We evaluate the accelerations for each case, using the formula: a = (vf - vi) / t

A) a = (10.3 - 0.5 ) / 1 = 9.8 m/s^2 --> magnitude: 9.8 m/s^2

B) a = (0 - 20) / 1 = - 20 m/s^2 --> magnitude : 20 m/s^2

C) a = (0.02 - 0.004) / 1 = 0.016 m/s^2 --> magnitude : 0.016 m/s^2

D) a = (4.3 - 0) / 0.4 = 10.75 m/s^2 --> magnitude : 10.75 m/s^2

E) a = (1 - 2) / 8.3 = - 0.12 m/s^2 --> magnitude: 0.12 m/s^2

Then, comparing magnitudes from least to greatest:

C , E , A , D , B

answered: Guest

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his discoveries about the moon, jupiter's moons, venus, and sunspots supported the idea that the sun - not the earth - was the center of the universe, as was commonly believed at the time.galileo turned his gaze toward venus, the brightest celestial object in the sky - other than the sun and the moon.

answered: Guest

i think the answer is a, hope this : )