Suppose the foreman had released the box from rest at a height of 0.25 m above the ground. What would the crate's speed be when it reaches the bottom of the ramp

v = 2.21 m/s

Explanation:

The foreman had released the box from rest at a height of 0.25 m above the ground.

We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :

So, its velocity at the bottom of the ramp is 2.21 m/s.

uranium fissions/breaks up giving out energy and neutrons