A 0.015kg hockey puck moving at 24m/s is caught and held by a 75kg goalie at rest. With what speed does the goalie slide on the ice?

0.0048m/s

Explanation:

Given parameters:

Mass of hockey = 0.015kg

Speed of the puck  = 24m/s

Unknown:

Mass of goalie  = ?

Solution:

The momentum of puck is a product of its mass and velocity;

     Momentum of puck  = 0.015 x 24  = 0.36kgm/s

According to the law of conservation of linear momentum,

  Momentum gained will be transferred to the goalie;

         Speed of goalie =

       Speed of goalie  =  = 0.0048m/s

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see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west