A car travelling at 15 m/s comes to rest in a distance of 14 m when the brakes are applied. Calculate the deceleration of the car.

-8.04 m/s2

Explanation:

To find the answer to this, you have to use the 4th kinematic equation:

You plug into the equation to get:

solve for a to get

-8.04 m/s2

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.