What is the maximum height a 95 W motor may vertically lift a 120 N weight in 6.2 s? a. 4.9 m b. 5.9 x 102 m c. 0.20 m d. 1.3 m

a. 4.9 m

Explanation:

To solve this problem we must take into account that power is defined as the relationship between the work and the time in which the work is done.

P = W/t

where:

P = power = 95 [W] (units of watts)

W = work [J] (units of Joules)

t = time = 6.2 [s]

We can clear the work from the previous equation.

W = P*t

W = 95*6.2 = 589 [J]

Now we know that the work is defined by the product of the force by the distance, therefore we can express the work done with the following equation.

W = F*d

where:

F = force = 120 [N] (units of Newtons)

d = distance [m]

d = W/F

d = 589/120

d = 4.9 [m]

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