What is the velocity of a 15.0 kg mass if its kinetic energy is 3.50 x 103 J? a. 467 m/s b. 0.0926 m/s c. 21.6 m/s d. 2.17 x 105 m/s

We are Given:

Mass (m) = 15 kg

KE = 3.5 * 10³ J

Velocity (v) = v m/s

Solving for the Velocity:

We know that:  KE=  1/2 mv²

replacing the variables

3.5 * 10 = 7.5 * v²

v² = 3.5 * 10³/ 7.5

v² = 466.67

v = √466.67

v = 21.6 m/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

the answer would be   dignified - apex