What is the maximum height a 95 W motor may vertically lift a 120 N weight in 6.2 s? a. 4.9 m b. 5.9 x 102 m c. 0.20 m d. 1.3 m

We are given:

Power of the motor(P)=  95 W

Weight of the object (F)= 120 N

time taken (t)=  6.2 s

Distance covered by the object (s) = s m

Solving for the distance covered:

We are given that the power of the motor = 95 W

we know that power = Work done / Time taken

So, Power = Force * displacement / Time taken                                                [Work done = Force * displacement]

replacing the variables

95 = (120 * s) / 6.2

s = 95*6.2 / 120

s = 4.9 m

c

explanation:

+15-35=-20

going in opposite directions