the angle between two vector A and B is theta .find the magnitude and direction of vector A×vectorB and vector A. vector B

The angle α which the resultant R makes with A is given by

tanα=

A+Bcosθ

Bsinθ

or

cos(θ/2)

sin(θ/2)

=

A+Bcosθ

2Bsin(θ/2)cos(θ/2)

which gives A+Bcosθ=2Bcos

2

(

2

θ

)

or A+B[2cos

2

(

2

θ

)−1]=2Bcos

2

(

2

θ

)

A=B

ill do it for 100, also this isnt 80 its 40