How much heat is released when 30 g of water at 96 °C cools to 16 °C ? The specific heat of water is 4184 J/kg°C

10 041.6 J

Explanation:

The equation for heat (energy) lost or gained by a system is

Q=mcΔT

Where Q is heat

m is the mass in kilograms

c is the specific heat of a substance

and T is the change in temperature

To start we convert 30g to kg by dividing by 1000

30/1000=0.03kg

We can now plug in all our values

Q= 0.03×4184×(96-16)= 10 041.6J

a, c, d, e are all applying about success strategies.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂