A rescue pilot wishes to drop a package of emergency supplies so that it lands as close as possible to a target. If the plane travels with a velocity of 18 m/s and is flying 225 m above the target, how far away (horizontally) from the target must the rescue pilot drop the package?

x = 121.86 m

Explanation:

It is given that,

The vertical velocity of a plane,

It is flying above the target, h = 225 m

First we will find the time taken by the plane to reach the ground. It can be calculated using the second equation of motion as follow :

Here, u = 0 and a = g

Let x is the horizontal distance from the target. It can be calculated as follows :

So, the rescue pilot drop the package at a distance of 121.86 m from the target.

an obstruction

total distance/total time

(85 + 82)/(5+3)

167/8

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