a driver travels 4.25 km in two minutes. if the driver's initial velocity is 20m/s, what is the acceleration

Recall the definition of average velocity:

average v = ∆x / ∆t

The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is

average v = (4250 m) / (120 s) ≈ 35.4 m/s

Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:

average v = (initial v + final v) / 2

Solve for (final v) :

35.4 m/s = (20 m/s + final v)/2

final v ≈ 50.83 m/s

Recall the definition of average acceleration:

average a = ∆v / ∆t

Solve for a :

a = (50.83 m/s - 20 m/s) / (120 s)

a ≈ 0.257 m/s²

volts times amps 6 x 0.5 3w

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.