A 925 N crate is being pulled across a level floor by a force F of 325 N at an angle of 25 above the
horizontal. The coefficient of kinetic friction is
0.25. Find the magnitude of the acceleration of
the crate.

The magnitude of the acceleration of  the crate is 1.033 m/s².

The given parameters;

The mass of the crate is calculated as;

W = mg

The normal force on the crate is calculated as;

Fₙ = 925 - 325 x sin(25)

Fₙ = 925 - 137.35

Fₙ = 787.65 N

The frictional force on the object is calculated as follows;

The magnitude of the crates acceleration is calculated from the net horizontal force on the crate;

Thus, the magnitude of the acceleration of  the crate is 1.033 m/s².

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change tension

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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