The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any work or heat interactions. Calculate the velocity at the exit of a diffuser when air at 100kPa and 20oC enters it with a velocity of 500 m/s and the exit is 200kPa and 90oC.

330.18m/s

Explanation:

Given data:

T1 = 20 °C

T2 = 90 °C

V = 500m/s

P1 = 100kpa

P2 = 200kpa.

Cp = 1.007kj/KgK

Solution:

Energy balance

Ein - Eout = change in Esystem.

We know

Exit velocity

V2 = (V1^2 + 2(h1 - h2)^0.5 = [V1^2 + 2Cp (T1-T2)]^0.5

input given data into the formula

V2 = [500^2 + 2 (1.007) * (20 - 90) * 1000/1 ]^0.5

V2 = 109020^0.5

V2 = 330.18m/s

Velocity at the exit is 330.18m/s

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).