14.4 K. L of heat is required to raise the temperature of a 12 kg substance from 275 K to 275.5 K. Identify the
substance

The substance is Ethanol

Explanation:

To solve this problem we must use the expression of thermal energy calculation that relates the mass of a body with the specific heat of this and the temperature difference.

Q = m*Cp*(T_f - T_i)

where:

Q = amount of heat = 14.4 [kJ]

m = mass = 12 [kg]

Cp = specific heat [kJ/kg*K]

T_f = final temperature = 275.5 [K]

T_i = initial temperature = 275 [K]

Therefore we need to calculate Cp, and then compare this with the values in the given table attached.

Cp = 14.4/(12*(275.5 - 275))

Cp = 2.4 [kJ/kg*K]

Now we compare the Cp with the values given in the table.

So the substance is Ethanol

where's the following? you gotta add it to know what the choices are

explanation: