A person ran with a speed of 6 m/s onto the skateboard .What is the speed with which he ride on the skate board

First, remember the conservation of energy.

We can define the kinetic energy as:

K = (1/2)*m*v^2

where m is the mass, and v is the velocity.

The velocity of the person is 6m/s, and the mass is unknown.

Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:

K' = (1/2)*(m + M)*v'^2

Where v' is the new velocity.

In this case, we can suppose that the skateboard has really small mass compared with the person.

M < < m

then:

(m + M) ≈ m

then:

K' = (1/2)*m*v'^2 = K = (1/2)*m*v^2

from that equation, we can conclude that:

v' = v

Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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