A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. It strikes a second hockey puck with a mass 0.11 kg. The first hockey puck comes to rest after the collision. What is the initial momentum of the system? (Round your answer to the nearest tenth.)

The initial momentum of the system is 2.6 kg·m/s to the nearest tenth

Explanation:

The given information are;

The mass of the first hockey puck, m₁ = 0.17 kg

The speed of the first hockey puck, v₁ = 15 m/s

The final speed of the first hockey puck, v₃ = 0 m/s (The first hockey puck comes to rest)

The mass of the second hockey puck, m₂ = 0.11 kg

The initial speed of the second hockey puck, v₂

Whereby the second hockey puck was initially at rest, we have v₂ = 0;

The initial momentum of the system = m₁v₁ + m₂v₂ = 0.17 × 15 + 0.11 × 0 = 2.55 kg·m/s

∴ The initial momentum of the system = 2.6 kg·m/s to the nearest tenth.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.