In a grocery store, you push a 15.5 kg shopping cart with a force of 10.5 N. If the cart starts at rest, how far does it move in 3.00 s?

The distance moved by the cart is 3.05 m

Explanation:

Given;

mass of the cart, m = 15.5 kg

applied force, f = 10.5 N

initial velocity, u = 0

time of motion, t = 3s

The final velocity of the cart is given by;

The acceleration of the cart is given by;

F = ma

a = F/m

a = 10.5 / 15.5

a = 0.677 m/s²

The horizontal distance moved by the cart is given by;

s = ut + ¹/₂at²

s = 0 + ¹/₂ (0.677)(3)²

s = 3.05 m

Therefore, the distance moved by the cart is 3.05 m

does anyone know or what?