At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 810 m/s2 and the vertical or y component of its acceleration is 910 m/s2. The ball's mass is 0.40 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

487.13N

Explanation:

According to Newton's second law;

F = ma

F is the net force

m is the mass of the object

a is the acceleration

First we need to find the resultant of the acceleration

a =√810²+910²

a = √656,100+828,100

a =√1,484,200

a = 1218.28m/s²

Ball mass = 0.40kg

Next is to get the magnitude of the net force

F = 0.4 × 1218.28

F = 487.31N

Hence the magnitude of the net force acting on the soccer ball at this instant is 487.13N

i believe the answer is a

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)