Find the recoil velocity of a 65kg ice hockey goalie who catches a 0.15kg hockey puck slapped at him at a velocity of 50m/s. Assume that the goalie is at rest before catching the puck, and friction between the ice and the puck-goalie system is negligible.

Explanation:

Given data

mass m1=65kg

velocity v1=?

mass m2=0.15kg

v2=50m/s

We know that the expression for the conservation of momentum is given as

0=m1v1+m2v2

we want to find v1

v1=(m2v2)/m1

v1=0.15*50/65

v1=7.5/65

v1=0.115

v1=0.12m/s

Therefore the recoil velocity is 0.12m/s

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer