A mountain biker is climbing a steep 20° slope at a constant speed. The cyclist and bike have a combined weight of 800 N. What can you say about the magnitude of the normal force of the ground on the bike?

The magnitude of the normal force of the ground on the bike is 751.752 N

The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:

F is the combined weight

is the angle of inclination

Given the following paramters

F = 800 N

= 20 degrees

Substitute the given parameters into the formula:

Hence the magnitude of the normal force of the ground on the bike is 751.752 N

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Normal force = 751.75 N

Explanation:

It is given that,

The combined weight of the cyclist and the bike is 800 N

We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :

mg = W, combined weight of cyclist and bike

So, the magnitude of the normal force of the ground on the bike is 751.75 N.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y