A box slides off a perfectly horizontal table with an initial speed of 2 m/s. The table is 1.5m off the ground. Vx = 2.0 m/s
1.5 m
What is the speed of the box just as it hits the ground?

The speed of the box just as it hits the ground is 5.8 m/s

Explanation:

Given;

initial velocity of the box, u = 2 m/s

height of the table, h = 1.5 m

The speed of the box, just before it hits the ground is given by;

v² = u² + 2gh

v² = (2)² + 2 x 9.8 x 1.5

v² = 4 + 29.4

v² = 33.4

v = √33.4

v = 5.8 m/s

Therefore, the speed of the box just as it hits the ground is 5.8 m/s

does anyone know or what?