Bert is standing on a ladder picking apples in his grandfather’s orchard. As he pulls each apple off the tree, he tosses it into a basket that sits on the ground 5.0 m below at a horizontal displacement of 2.0 m from Bert. About how fast must Bert throw the apples (horizontally) in order to land in the basket?

10.3 m/s

Explanation:

Given that Bert is standing on a ladder picking apples in his grandfather’s orchard. As he pulls each apple off the tree, he tosses it into a basket that sits on the ground 5.0 m below at a horizontal displacement of 2.0 m from Bert.

Let us use pythagorean theorem

H = sqrt ( 5^2 + 2^2 )

H = sqrt ( 25 + 4 )

H = sqrt ( 29 )

H = 5.385 m

Using the third equation of motion

V^2 = U^2 + 2gH

But U = 0

V^2 = 2 × 9.8 × 5.385

V^2 = 105.549

V = sqrt ( 105.549 )

V = 10.27 m/s

Therefore, Bert will throw the apples (horizontally) in order to land in the basket as fast as 10.3 m/s approximately.

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.