The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 5, m2 = 4, m3 = 3, m4 = 6; P1(−4, 3), P2(0, 5), P3(3, 2), P4(1, −2)

The center of mass of the system at the given points (-0.278, 1.61).

The given parameters;

The total mass is calculated as follows;

m = 5 + 4 + 3 + 6 = 18

The sum of the masses on the on x and y-direction;

The center mass is calculated as follows;

Thus, the center of mass of the system at the given points (-0.278, 1.61).

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Answer with Explanation:

We are given that

We have to find Mx ,My and center of mass of the system.

Total mass,m=m1+m2+m3+m4=5+4+3+6=18

Center of mass=(-5/18,29/18)

f=ma newton

f=100x2.5=250n