Consider an ionic compound, MXMX , composed of generic metal MM and generic, gaseous halogen XX . The enthalpy of formation of MXMX is ΔH∘f=−421ΔHf∘=−421 kJ/mol. The enthalpy of sublimation of MM is ΔHsub=155ΔHsub=155 kJ/mol. The ionization energy of MM is IE=401IE=401 kJ/mol. The electron affinity of XX is ΔHEA=−321ΔHEA=−321 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=239BE=239 kJ/mol. Determine the lattice energy of MXMX .

- 775.5 kJ/mol

Explanation:

Given that:

The enthalpy of formation of MX is = - 421 kJ/mol

The enthalpy of sublimation of MM is =  155  kJ/mol

The ionization energy of MM is  = 401 kJ/mol

The electron affinity of XX is   = -321 kJ/mol

The bond energy of X2 is BE = 239 J/mol

The process for each above component is shown below:

Thus, the overall reaction is:

The overall energy is:

- 421 kJ/mol = U + 155 kJ/mol + 401 kJ/mol + 119.5 kJ/mol + (-321 kJ/mol)

- 421 kJ/mol = U + 354.5 kJ/mol

- U = 421 kJ/mol + 354.5 kJ/mol

- U = 421 kJ/mol + 354.5 kJ/mol

- U = 775.5 kJ/mol

U = - 775.5 kJ/mol

Thus, the lattice energy of MX (U) = - 775.5 kJ/mol

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