what is the diameter of the wire 1.4*10^16 electrons flow through a cross section of silver wire in 290 with a drift speed of 7*10^-4

The diameter is

Explanation:

From the question we are told that

   The number of electrons is  

    The time taken is  

     The drift speed is  

Generally the number of electrons  that flows through the cross-sectional  area at the given time t is mathematically represented as

Here n is the number of conduction  electrons present in and the value is  

A  is the cross-sectional area of the wire

So  

=>  

Gnerally the area is mathematically represented as

=>  

=>  

=>  

=>  

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer