. A car is traveling in a straight line path at a maximum speed of 7.00 m/s. The driver of the vehicle applies the brakes bringing the car to a stop after traveling 10.0 m. What is the magnitude of the car's acceleration to the nearest hundredths place?

Acceleration = -2.45 m/s²

Explanation:

Given:

Initial speed u = 7 m/s

Final speed v = 0 m/s

Distance s  = 10 m

Find:

Acceleration

Computation:

v² = u² + 2as

0² = 7² + 2a(10)

0 = 49 + 20 a

-49 / 20 = a

Acceleration = -2.45 m/s²

less than one you can't create energy

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.