10.0 mF parallel-plate capacitor with circular plates is connected to a 12.0 V battery. (a) What is the charge on each plate

0.12 C.

Explanation:

The following data were obtained from the question:

Capacitor (C) = 10 mF

Potential difference (V) = 12 V

Charge (Q) =?

Next, we shall convert 10 mF to farad (F). This can be obtained as follow:

1 mF = 1×10¯³ F

Therefore,

10 mF = 10 mF × 1×10¯³ F/ 1mF

10 mF = 0.01 F

Therefore, 10 mF is equivalent to 0.01 F.

Finally, we shall determine the charge on the capacitor as illustrated below:

Capacitor (C) = 0.01 F

Potential difference (V) = 12 V

Charge (Q) =?

Q = CV

Q = 0.01 × 12

Q = 0.12 C

Therefore, the charge on the capacitor is 0.12 C.

d is the answer i came up with

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..