PLEASE HELP ASAP A golf ball is hit horizontally off the edge of a 30 m high cliff and lands
distance of 25 m from the edge of the cliff.

1. What is the initial vertical velocity of the golf ball?

2. At what time did the golf ball hit the ground?

3. What was the initial horizontal velocity of the golf ball?

4. What was the final horizontal velocity of the golf ball?

1. Initial vertical velocity its 0m/s

2. 2.47 seconds

3. 10.12 m/s

4.10.12 m/s

Explanation:

Remember that we have here two parts of a problem, first we know that the ball made a free fall of 30 meters, since the ball was hit horizontally and doesn't state otherwise the vertical velocity is 0. To calculate the time we just use 30 m as our Height and use the formula for vertical distance on free fall:

Now we just solve for time:

With this we just insert the values we know:

Now we know that the ball was 2.47 seconds in the air, so the ball hti the ground at the second 2.47.

To calculate the velocity of the ball we just need to divide the horizontal distance covered by the time it spent on air:

The final and initial horizontal velocity of the ball would be the same since nothing states otherwise, of course the hitting of the ground would decrease its velocity but since nothing is said in the problem it is not considered.

the results is a decrease in air temperature with an increase of altitude.

explanation:

c. newton's third law of motion