Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150 m from both antennas measures an intensity I0. The receiver is moved so that it is 1.8 m closer to one antenna than to the other. (a) What is the phase difference f between the two radio waves produced by this path difference? (b) In terms of I0, what is the intensity measured by the receiver at its new position?

a

b

Explanation:

From the question we are told that

  The distance of separation is  

  The frequency is

   The distance of the receiver from the antennas is

   The intensity measured is  

    The change in position of the receiver is by  

Gnerally the phase difference is mathematically represented as

Here  is the wavelength which is mathematically represented as

Here c is the speed of light with value  

=>    

=>    

=>    

So

Generally the intensity measured by the receiver is  

=>  

=>  

=>  

i believe the answer is a