A van slows down uniformly from 17 m/s to 0 m/s in 5 s. How far does it travel before stopping? Procedure is required.

Before stopping, the van travels 42.5 m

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

The distance traveled by the object is given by:

The van slows down uniformly from v0=17 m/s to vf=0 m/s in t=5 s. The acceleration can be calculated by solving [1] for a:

The distance covered is:

Before stopping, the van travels 42.5 m

it breaks and dirupture other materials and other sencews from the bottom