An object accelerates from rest to a velocity of 34 m/s over a distance of 70 m. What was its acceleration?

6.8m/s²

Explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity  = 34m/s

Distance  = 70m

Unknown:

To solve this problem we apply one of the motion equations;

     V²   = U² + 2aS

where V is the final velocity

           U is the initial velocity

           a is the acceleration

         S is the distance covered

Input the parameters and solve;

   34² = 0² + 2 x a x 70

  34² = 140a

   a  = 6.8m/s²

found in the nucleus

has mass of one amu