The electric field between two parallel plates has a magnitude of 180 N/C. The two plates are 2.5 cm apart.
Recall that the magnitude of the charge on an electron is
1.602 x 10-19 C.
How much work is done to move an electron from the
positive plate to the negative plate?

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we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg