Physics, 19.10.2020 14:01, alexianunez15
A stone is projected vertically upward with a velocity of 20 metre per second. 2 seconds later a second stone to is similarly projected with the same velocity when the two stones meet the second one is rising at a velocity of 10 metre per second neglecting air resistance calculate the length of time the second stone is in motion before they meet to velocity of the first Stone when they meet take g equals to 10 metre per second
Answers: 2
Other questions on the subject: Physics
Physics, 22.06.2019 15:00, sswd
Steelhead trout migrate up stream to spawn. occasionally they need to leap up small waterfalls to continue their journey. fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of 8.0 m/s. a. what is the maximum height a steelhead trout can jump? b. leaving the water at 8.0 m/s, the trout lands on top of the water fall 1.8 m high. how long was it in the air?
Answers: 2
Do you know the correct answer?
A stone is projected vertically upward with a velocity of 20 metre per second. 2 seconds later a sec...
Questions in other subjects:
Health, 12.12.2020 16:00
Chemistry, 12.12.2020 16:00
