A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?

8 m/s².

Explanation:

We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:

Mass (m) = 0.25 Kg

Acceleration (a) = 16 m/s²

Force (F) =.?

Force (F) = mass (m) × acceleration (a)

F = ma

F = 0.25 × 16

F = 4 N

Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.

Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:

Mass (m) = 0.50 Kg

Force (F) = 4 N

Acceleration (a) =?

F = ma

4 = 0.5 × a

Divide both side by 0.5

a = 4 / 0.5

a = 8 m/s²

Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².

c) up is the direction the magnetic force is acting on the charge.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)