An empty 50-g bowl rests on a scale that measures force (in newtons). Water is then poured into the scale from a height of 0.50 m and rate of 10 mL/s. Assuming that the water does not splash as it comes to rest, calculate the reading on the scale at t = 5.0 s

1 Newton

Explanation:

Mass of bowl (Mb) = 50 g = 0.05 kg

Initial Velocity (Vo) = 10 mL/s = 10g/s

time (t) = 5.0s

Mass of water (Mw) = 10 g/s * 5s = 50 g = 0.05 kg

*Vob = initial velocity of bowl

*Vow = initial velocity of water

*Vf = final velocity

*g = gravity = 9.8

Conservation of momentum [Inelastic Collision]:

Impulse-Momentum Theorem:

Scale Reading:

i believe the answer is a

true is the correct answer

hope i