the total mass of ship, including cargo on board, is 1200000kg, if it floats in sea calculate the volume of the sea water it displaces? take relative density of the sea water =1.03

The density of sea water is 1.03 × 103 kg m^–3. A ship of 10.1 × 106 N weight floats on it. The ship then enters the fresh water and some cargo is unloaded. Then what is the volume of sea water displaced?

Options are:

1. volume of sea water displaced is 103 m3

2. volume of sea water displaced 3 × 104 kg

3. A is incorrect

4. B is incorrect

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

see earlier