a car on a circular track accelerates from rest. the radius of the track is 0.30km and the magnitude of the constant angular acceleration is 4.5x10-3 rads/s squared. find the centripetal acceleration of the car when it has completed half of a lap.

The centripetal acceleration of the car is 50.4 m/s²

Explanation:

Given;

radius of the track, r = 0.3km = 300 m

constant angular acceleration, α = 4.5 x 10⁻³ rad/s²

during half of a lap, θ = π

Determine time of motion

θ = ωt + ¹/₂αt²

π = 0 + ¹/₂αt²

t² = 2π / α

t² = ( 2 x 3.142) / (4.5 x 10⁻³)

t² = 1396.44

t = √1396.44

t = 37.369 s

Determine the angular velocity

Determine the centripetal acceleration of the car

Therefore, the centripetal acceleration of the car is 50.4 m/s²

a) are muscles that have bands.

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answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.