You are designing an apparatus to shoot a water balloon through a 3rd story window (25m above the ground)

The balloon needs a vertical velocity of approximately 22.14 m/s to reach the window

Explanation:

The given parameters are;

The destination of the designed water balloon we shoot = The 3rd story window

The height of the 3rd story window which the water balloon should reach = 25 m

Therefore, we have, the equation of motion of the water balloon given as follows;

v² = u² - 2 × g × s

Where;

= The initial vertical velocity of the balloon

= The final vertical velocity of the balloon = 0 m/s

g = The acceleration due to gravity = 9.8 m/s

s = The height the balloon is intended reach at the final velocity becomes 0 m/s = The height of the 3rd story window

∴ s = 25 m

Substituting the values, we have;

0² = ² - 2 × 9.8 × 25

² = 2 × 9.8 × 25 = 490

= √490 = 7·√10

The initial vertical velocity of the balloon = = 7·√10 m/s

Therefore, the balloon needs a vertical velocity of 7·√10 m/s which is approximately 22.14 m/s to reach the window.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle