What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds

Explanation:

Given that,

Initial velocity, u = -2 m/s

Final velocity, v = =.5 m/s

Time, t = 0.025 s

We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.

So, the acceleration of the jet is .

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

the correct answer is "inertia"