Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of +25.0 μC and the instrument indicates that the electric force exerted on it is 40.0 μN, due east. What are the magnitude and direction of the electric field? E = (b) What are the magnitude and direction of the electric field if the object has a charge of -10.0 μC and the instrument indicates that the force is 40.0 μN, due west? E = (Chp18,p13GO)

(a) 1.6 N/C, due east.

(b) 4 N/C, due east.

Explanation:

The force vector, on the charge, q, in the electric field vector, , is

Let the unit vector towards east is , so the unit vector towards west is -

(a) Given that:

,

, due east

From equation (i)

So, the magnitude of electric field is 1.6 N/C and the direction is towards east.

(b) Given that:

,

, due west

From equation (i)

So, the magnitude of electric field is 4 N/C and the direction is towards the east.

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.

i believe the answer is electric potential.

explanation: