Urgent please help. it’s kinematic equations

A:

The displacement is 0 meters because it just moved back to its original position.

The distance traveled(in meters) is just the speed times the time, which is 18 m/s * 3600 s = 64800 meters.

B:

In this case, the displacement and the distance traveled are the same because the object didn't change direction.

The distance traveled(in meters) and the displacement is just the speed times the time, which is 16 m/s * 15 s = 240 meters.

C:

In this case, the displacement and the distance traveled are the same because the object didn't change direction.

We can use the equation (Final Velocity)^2 = (Initial Velocity)^2 + 2*Acceleration*Distance.

Now we can plug the known values: (5)^2 = (20)^2 + 2*(-4)*d, and now we solve for d: 25 = 400 + -8d -> -375 = -8d -> d = 46.875 meters.

D:

Again, in this case, the displacement and the distance traveled are the same because the object didn't change direction.

We can use the equation Distance = (Initial Velocity) * (Time) + 1/2 * (Acceleration) * (Time)^2.

Plugging in the values we know, we get d = 0*20 + 1/2*3.7*20^2 -> d = 740 meters.

E:

Again, in this case, the displacement and the distance traveled are the same because the object didn't change direction.

We can use the equation Distance = (Initial Velocity) * (Time) + 1/2 * (Acceleration) * (Time)^2.

Plugging in the values we know, we get d = 12*26 + 1/2*1.5*26^2 -> d = 819 meters.

If you have further questions please don't hesitate to ask.

I really hoped this helped you, and if it did, could you please consider giving me a brainliest? :)

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