10-When a car driver sees an emergency ahead, he applies the brakes. During his reaction time the cartravels at a steady speed and covers a distance known as the thinking distance. The braking distance is thedistance travelled by the car after the brakes are applied.(a)State the energy change that occurs as the car brakes. [2](b)Fig. 9.1 shows the speed-time graph of a car. The driver sees the emergency at time t = 0.The total mass of the car is 800 kg find the thinking distance
braking distance and
the deceleration of the car during braking,

(iv) the force provided by the brakes.
(c) Using ideas about friction and deceleration, state and explain how the braking distance is affected by
(i) using new tyres rather than badly worn tyres, .

For me a person with a phd and who knows what there talking about.i know the chances of a radiation leak is low but if it does the area within a 96.3 mile radius would be unusable because of contamination

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge

Answerthe distance between the two ends of the galaxy is 150,000 light years;