A dog chasing a cat has 0.55 times the kinetic energy of the cat, which has 0.45 times the weight of the dog. The dog speeds up by 0.91 m/s and then has the same kinetic energy as the cat. What was the original difference in speed of the dog and cat? In other words, what is v_sub_cat - v_sub_dog initially (before the dog speeds up)?

The difference in speed of the dog and cat is 2.65 m/s

Explanation:

Given that,

Mass of cat = 0.45 times the mass of dog

K.E of dog = 0.55 times K.E of cat

We need to calculate the velocity of dog

Using given data

....(I)

The dog speeds up by 0.91 m/s and then has the same kinetic energy as the cat.

We need to calculate the velocity of dog

Using conservation of kinetic energy,

...(II)

From equation (I) and (II)

Put the value in equation (I)

We need to calculate the difference in speed of the dog and cat

Using speed of dog and cat

Hence, The difference in speed of the dog and cat is 2.65 m/s

d. platinum would have the greatest temperature increase because it has the lowest specific heat.

option number c is the right answer.