3) In the figure below, a ball is thrown from point A on top of an inclined plane of = 57°, with an initial velocity V0 and an angle . The ball takes 1.25 seconds to reach the maximum height of its trajectory (point B) and at this moment it is at a horizontal distance D = 3.7 m from the launch point. For this situation, calculate (a) the launch angle; (b) the initial velocity V0; (c) the total flight time between points A and C; (d) the velocity of the ball at the instant it reaches point C; and (e) the distance D between the launch point and the impact point. Tip: use the relationship sen(a)/cos(a)=tg(a)

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Answermake them get very hot and over time wear them out;

Ibelieve the answer is arteries